Merge #10255: [test] Add test for listaddressgroupings
dadfee3 [test] Add test for listaddressgroupings (Jimmy Song) Tree-SHA512: 21cf0233c7fcf585f9a31306612ae1113ea916d2972b834efef0cb2154bd4dd24d9746d0632c778c699328f7e7a336d2da6e2bac9f0fb657c30290757563ad22
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@ -7,6 +7,7 @@
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RPCs tested are:
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- getaccountaddress
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- getaddressesbyaccount
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- listaddressgroupings
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- setaccount
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- sendfrom (with account arguments)
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- move (with account arguments)
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@ -31,10 +32,51 @@ class WalletAccountsTest(BitcoinTestFramework):
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# Check that there's no UTXO on any of the nodes
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assert_equal(len(node.listunspent()), 0)
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# Note each time we call generate, all generated coins go into
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# the same address, so we call twice to get two addresses w/50 each
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node.generate(1)
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node.generate(101)
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assert_equal(node.getbalance(), 1000)
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assert_equal(node.getbalance(), 500)
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# there should be 2 address groups
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# each with 1 address with a balance of 500 Dash
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address_groups = node.listaddressgroupings()
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assert_equal(len(address_groups), 2)
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# the addresses aren't linked now, but will be after we send to the
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# common address
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linked_addresses = set()
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for address_group in address_groups:
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assert_equal(len(address_group), 1)
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assert_equal(len(address_group[0]), 2)
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assert_equal(address_group[0][1], 500)
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linked_addresses.add(address_group[0][0])
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# send 500 from each address to a third address not in this wallet
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# There's some fee that will come back to us when the miner reward
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# matures.
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common_address = "msf4WtN1YQKXvNtvdFYt9JBnUD2FB41kjr"
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txid = node.sendmany(
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fromaccount="",
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amounts={common_address: 100},
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subtractfeefrom=[common_address],
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minconf=1,
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)
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tx_details = node.gettransaction(txid)
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fee = -tx_details['details'][0]['fee']
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# there should be 1 address group, with the previously
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# unlinked addresses now linked (they both have 0 balance)
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address_groups = node.listaddressgroupings()
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assert_equal(len(address_groups), 1)
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assert_equal(len(address_groups[0]), 2)
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assert_equal(set([a[0] for a in address_groups[0]]), linked_addresses)
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assert_equal([a[1] for a in address_groups[0]], [0, 0])
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node.generate(1)
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# we want to reset so that the "" account has what's expected.
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# otherwise we're off by exactly the fee amount as that's mined
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# and matures in the next 100 blocks
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node.sendfrom("", common_address, fee)
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accounts = ["a", "b", "c", "d", "e"]
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amount_to_send = 1.0
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account_addresses = dict()
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