Commit Graph

6 Commits

Author SHA1 Message Date
Matt Corallo
e3f315a0a5 Fix python usage for arch's broken maintainers 2014-11-27 00:02:28 -05:00
Wladimir J. van der Laan
b6c99efe9c
Merge pull request #5121
214091d Update license in pull-tester and rpc-tests (Michael Ford)
2014-10-27 13:48:45 +01:00
Daniel Kraft
dcb98466b4 Extend getchaintips RPC test.
Add the capability to simulate network splits to the RPC test framework
and use it to do more extensive testing of 'getchaintips'.
2014-10-24 08:53:04 +02:00
Michael Ford
214091d584 Update license in pull-tester and rpc-tests
Add missing copyright/license header where necessary
2014-10-23 09:48:19 +08:00
Gavin Andresen
e8097f7df1
Refactor common RPC test code to BitcoinTestFramework base class
Inspired by #3956, with a little more flexibility built in.

I didn't touch rpcbind_test.py, because it only runs on Linux.
2014-07-09 10:19:26 -04:00
Gavin Andresen
171ca7745e estimatefee / estimatepriority RPC methods
New RPC methods: return an estimate of the fee (or priority) a
transaction needs to be likely to confirm in a given number of
blocks.

Mike Hearn created the first version of this method for estimating fees.
It works as follows:

For transactions that took 1 to N (I picked N=25) blocks to confirm,
keep N buckets with at most 100 entries in each recording the
fees-per-kilobyte paid by those transactions.

(separate buckets are kept for transactions that confirmed because
they are high-priority)

The buckets are filled as blocks are found, and are saved/restored
in a new fee_estiamtes.dat file in the data directory.

A few variations on Mike's initial scheme:

To estimate the fee needed for a transaction to confirm in X buckets,
all of the samples in all of the buckets are used and a median of
all of the data is used to make the estimate. For example, imagine
25 buckets each containing the full 100 entries. Those 2,500 samples
are sorted, and the estimate of the fee needed to confirm in the very
next block is the 50'th-highest-fee-entry in that sorted list; the
estimate of the fee needed to confirm in the next two blocks is the
150'th-highest-fee-entry, etc.

That algorithm has the nice property that estimates of how much fee
you need to pay to get confirmed in block N will always be greater
than or equal to the estimate for block N+1. It would clearly be wrong
to say "pay 11 uBTC and you'll get confirmed in 3 blocks, but pay
12 uBTC and it will take LONGER".

A single block will not contribute more than 10 entries to any one
bucket, so a single miner and a large block cannot overwhelm
the estimates.
2014-06-06 10:44:57 -04:00