neobytes/qa/rpc-tests/llmq-is-retroactive.py
2019-12-07 00:35:27 +01:00

180 lines
9.0 KiB
Python
Executable File

#!/usr/bin/env python3
# Copyright (c) 2015-2018 The Dash Core developers
# Distributed under the MIT software license, see the accompanying
# file COPYING or http://www.opensource.org/licenses/mit-license.php.
from test_framework.mininode import *
from test_framework.test_framework import DashTestFramework
from test_framework.util import sync_blocks, set_node_times, \
isolate_node, reconnect_isolated_node, set_mocktime, get_mocktime
'''
llmq-is-retroactive.py
Tests retroactive signing
We have 6 nodes where node 0 is the control node, nodes 1-5 are masternodes.
Mempool inconsistencies are simulated via disconnecting/reconnecting node 3
and by having a higher relay fee on nodes 4 and 5.
'''
class LLMQ_IS_RetroactiveSigning(DashTestFramework):
def __init__(self):
# -whitelist is needed to avoid the trickling logic on node0
super().__init__(6, 5, [["-whitelist=127.0.0.1"], [], [], [], ["-minrelaytxfee=0.001"], ["-minrelaytxfee=0.001"]], fast_dip3_enforcement=True)
def run_test(self):
while self.nodes[0].getblockchaininfo()["bip9_softforks"]["dip0008"]["status"] != "active":
self.nodes[0].generate(10)
sync_blocks(self.nodes, timeout=60*5)
self.nodes[0].spork("SPORK_17_QUORUM_DKG_ENABLED", 0)
self.nodes[0].spork("SPORK_19_CHAINLOCKS_ENABLED", 0)
self.nodes[0].spork("SPORK_2_INSTANTSEND_ENABLED", 0)
self.nodes[0].spork("SPORK_3_INSTANTSEND_BLOCK_FILTERING", 0)
self.nodes[0].spork("SPORK_20_INSTANTSEND_LLMQ_BASED", 0)
self.wait_for_sporks_same()
self.mine_quorum()
self.mine_quorum()
# Make sure that all nodes are chainlocked at the same height before starting actual tests
self.wait_for_chainlocked_block_all_nodes(self.nodes[0].getbestblockhash())
self.log.info("trying normal IS lock")
txid = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), 1)
# 3 nodes should be enough to create an IS lock even if nodes 4 and 5 (which have no tx itself)
# are the only "neighbours" in intra-quorum connections for one of them.
self.wait_for_instantlock(txid, self.nodes[0], do_assert=True)
set_mocktime(get_mocktime() + 1)
set_node_times(self.nodes, get_mocktime())
block = self.nodes[0].generate(1)[0]
self.wait_for_chainlocked_block_all_nodes(block)
self.log.info("testing normal signing with partially known TX")
isolate_node(self.nodes[3])
txid = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), 1)
# Make sure nodes 1 and 2 received the TX before we continue,
# otherwise it might announce the TX to node 3 when reconnecting
self.wait_for_tx(txid, self.nodes[1])
self.wait_for_tx(txid, self.nodes[2])
reconnect_isolated_node(self.nodes[3], 0)
self.wait_for_mnauth(self.nodes[3], 2)
# node 3 fully reconnected but the TX wasn't relayed to it, so there should be no IS lock
self.wait_for_instantlock(txid, self.nodes[0], False, 5, do_assert=True)
# push the tx directly via rpc
self.nodes[3].sendrawtransaction(self.nodes[0].getrawtransaction(txid))
# node 3 should vote on a tx now since it became aware of it via sendrawtransaction
# and this should be enough to complete an IS lock
self.wait_for_instantlock(txid, self.nodes[0], do_assert=True)
self.log.info("testing retroactive signing with unknown TX")
isolate_node(self.nodes[3])
rawtx = self.nodes[0].createrawtransaction([], {self.nodes[0].getnewaddress(): 1})
rawtx = self.nodes[0].fundrawtransaction(rawtx)['hex']
rawtx = self.nodes[0].signrawtransaction(rawtx)['hex']
txid = self.nodes[3].sendrawtransaction(rawtx)
# Make node 3 consider the TX as safe
set_mocktime(get_mocktime() + 10 * 60 + 1)
set_node_times(self.nodes, get_mocktime())
block = self.nodes[3].generatetoaddress(1, self.nodes[0].getnewaddress())[0]
reconnect_isolated_node(self.nodes[3], 0)
self.wait_for_chainlocked_block_all_nodes(block)
self.nodes[0].setmocktime(get_mocktime())
self.log.info("testing retroactive signing with partially known TX")
isolate_node(self.nodes[3])
txid = self.nodes[0].sendtoaddress(self.nodes[0].getnewaddress(), 1)
# Make sure nodes 1 and 2 received the TX before we continue,
# otherwise it might announce the TX to node 3 when reconnecting
self.wait_for_tx(txid, self.nodes[1])
self.wait_for_tx(txid, self.nodes[2])
reconnect_isolated_node(self.nodes[3], 0)
self.wait_for_mnauth(self.nodes[3], 2)
# node 3 fully reconnected but the TX wasn't relayed to it, so there should be no IS lock
self.wait_for_instantlock(txid, self.nodes[0], False, 5, do_assert=True)
# Make node0 consider the TX as safe
set_mocktime(get_mocktime() + 10 * 60 + 1)
set_node_times(self.nodes, get_mocktime())
block = self.nodes[0].generate(1)[0]
self.wait_for_chainlocked_block_all_nodes(block)
self.log.info("testing retroactive signing with partially known TX and all nodes session timeout")
self.test_all_nodes_session_timeout(False)
self.log.info("repeating test, but with cycled LLMQs")
self.test_all_nodes_session_timeout(True)
self.log.info("testing retroactive signing with partially known TX and single node session timeout")
self.test_single_node_session_timeout(False)
self.log.info("repeating test, but with cycled LLMQs")
self.test_single_node_session_timeout(True)
def cycle_llmqs(self):
self.mine_quorum()
self.mine_quorum()
self.wait_for_chainlocked_block_all_nodes(self.nodes[0].getbestblockhash())
def test_all_nodes_session_timeout(self, do_cycle_llmqs):
set_node_times(self.nodes, get_mocktime())
isolate_node(self.nodes[3])
rawtx = self.nodes[0].createrawtransaction([], {self.nodes[0].getnewaddress(): 1})
rawtx = self.nodes[0].fundrawtransaction(rawtx)['hex']
rawtx = self.nodes[0].signrawtransaction(rawtx)['hex']
txid = self.nodes[0].sendrawtransaction(rawtx)
txid = self.nodes[3].sendrawtransaction(rawtx)
# Make sure nodes 1 and 2 received the TX before we continue
self.wait_for_tx(txid, self.nodes[1])
self.wait_for_tx(txid, self.nodes[2])
# Make sure signing is done on nodes 1 and 2 (it's async)
time.sleep(5)
# Make the signing session for the IS lock timeout on nodes 1-3
set_mocktime(get_mocktime() + 61)
set_node_times(self.nodes, get_mocktime())
time.sleep(2) # make sure Cleanup() is called
reconnect_isolated_node(self.nodes[3], 0)
self.wait_for_mnauth(self.nodes[3], 2)
# node 3 fully reconnected but the signing session is already timed out on all nodes, so no IS lock
self.wait_for_instantlock(txid, self.nodes[0], False, 5, do_assert=True)
if do_cycle_llmqs:
self.cycle_llmqs()
self.wait_for_instantlock(txid, self.nodes[0], False, 5, do_assert=True)
# Make node 0 consider the TX as safe
set_mocktime(get_mocktime() + 10 * 60 + 1)
self.nodes[0].setmocktime(get_mocktime())
block = self.nodes[0].generate(1)[0]
self.wait_for_chainlocked_block_all_nodes(block)
def test_single_node_session_timeout(self, do_cycle_llmqs):
set_node_times(self.nodes, get_mocktime())
isolate_node(self.nodes[3])
rawtx = self.nodes[0].createrawtransaction([], {self.nodes[0].getnewaddress(): 1})
rawtx = self.nodes[0].fundrawtransaction(rawtx)['hex']
rawtx = self.nodes[0].signrawtransaction(rawtx)['hex']
txid = self.nodes[3].sendrawtransaction(rawtx)
time.sleep(2) # make sure signing is done on node 2 (it's async)
# Make the signing session for the IS lock timeout on node 3
set_mocktime(get_mocktime() + 61)
set_node_times(self.nodes, get_mocktime())
time.sleep(2) # make sure Cleanup() is called
reconnect_isolated_node(self.nodes[3], 0)
self.wait_for_mnauth(self.nodes[3], 2)
self.nodes[0].sendrawtransaction(rawtx)
# Make sure nodes 1 and 2 received the TX
self.wait_for_tx(txid, self.nodes[1])
self.wait_for_tx(txid, self.nodes[2])
# Make sure signing is done on nodes 1 and 2 (it's async)
time.sleep(5)
# node 3 fully reconnected but the signing session is already timed out on it, so no IS lock
self.wait_for_instantlock(txid, self.nodes[0], False, 1, do_assert=True)
if do_cycle_llmqs:
self.cycle_llmqs()
self.wait_for_instantlock(txid, self.nodes[0], False, 5, do_assert=True)
# Make node 0 consider the TX as safe
set_mocktime(get_mocktime() + 10 * 60 + 1)
self.nodes[0].setmocktime(get_mocktime())
block = self.nodes[0].generate(1)[0]
self.wait_for_chainlocked_block_all_nodes(block)
if __name__ == '__main__':
LLMQ_IS_RetroactiveSigning().main()