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Port test to rpc-test framework
This commit is contained in:
Suhas Daftuar
Peter Todd
parent
20367d831f
commit
97203f5606
@ -92,6 +92,7 @@ testScriptsExt = [
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'p2p-acceptblock.py',
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'mempool_packages.py',
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'maxuploadtarget.py',
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'replace-by-fee.py',
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]
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#Enable ZMQ tests
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512
qa/rpc-tests/replace-by-fee.py
Executable file
512
qa/rpc-tests/replace-by-fee.py
Executable file
@ -0,0 +1,512 @@
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#!/usr/bin/env python2
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# Copyright (c) 2014-2015 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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#
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# Test replace by fee code
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#
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import *
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from test_framework.script import *
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from test_framework.mininode import *
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import binascii
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COIN = 100000000
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MAX_REPLACEMENT_LIMIT = 100
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def satoshi_round(amount):
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return Decimal(amount).quantize(Decimal('0.00000001'), rounding=ROUND_DOWN)
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def txToHex(tx):
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return binascii.hexlify(tx.serialize()).decode('utf-8')
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def make_utxo(node, amount, confirmed=True, scriptPubKey=CScript([1])):
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"""Create a txout with a given amount and scriptPubKey
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Mines coins as needed.
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confirmed - txouts created will be confirmed in the blockchain;
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unconfirmed otherwise.
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"""
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fee = 1*COIN
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while node.getbalance() < satoshi_round((amount + fee)/COIN):
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node.generate(100)
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#print (node.getbalance(), amount, fee)
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new_addr = node.getnewaddress()
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#print new_addr
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txid = node.sendtoaddress(new_addr, satoshi_round((amount+fee)/COIN))
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tx1 = node.getrawtransaction(txid, 1)
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txid = int(txid, 16)
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i = None
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for i, txout in enumerate(tx1['vout']):
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#print i, txout['scriptPubKey']['addresses']
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if txout['scriptPubKey']['addresses'] == [new_addr]:
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#print i
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break
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assert i is not None
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tx2 = CTransaction()
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tx2.vin = [CTxIn(COutPoint(txid, i))]
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tx2.vout = [CTxOut(amount, scriptPubKey)]
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tx2.rehash()
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tx2_hex = binascii.hexlify(tx2.serialize()).decode('utf-8')
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#print tx2_hex
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signed_tx = node.signrawtransaction(binascii.hexlify(tx2.serialize()).decode('utf-8'))
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txid = node.sendrawtransaction(signed_tx['hex'], True)
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# If requested, ensure txouts are confirmed.
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if confirmed:
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while len(node.getrawmempool()):
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node.generate(1)
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return COutPoint(int(txid, 16), 0)
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class ReplaceByFeeTest(BitcoinTestFramework):
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def setup_network(self):
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self.nodes = []
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self.nodes.append(start_node(0, self.options.tmpdir, ["-maxorphantx=1000",
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"-relaypriority=0", "-whitelist=127.0.0.1"]))
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self.is_network_split = False
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def run_test(self):
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make_utxo(self.nodes[0], 1*COIN)
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print "Running test simple doublespend..."
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self.test_simple_doublespend()
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print "Running test doublespend chain..."
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self.test_doublespend_chain()
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print "Running test doublespend tree..."
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self.test_doublespend_tree()
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print "Running test replacement feeperkb..."
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self.test_replacement_feeperkb()
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print "Running test spends of conflicting outputs..."
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self.test_spends_of_conflicting_outputs()
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print "Running test new unconfirmed inputs..."
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self.test_new_unconfirmed_inputs()
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print "Running test too many replacements..."
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self.test_too_many_replacements()
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print "Running test opt-in..."
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self.test_opt_in()
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print "Passed\n"
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def test_simple_doublespend(self):
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"""Simple doublespend"""
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tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
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tx1a = CTransaction()
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tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
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tx1a_hex = txToHex(tx1a)
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tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
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# Should fail because we haven't changed the fee
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tx1b = CTransaction()
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tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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tx1b.vout = [CTxOut(1*COIN, CScript([b'b']))]
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tx1b_hex = txToHex(tx1b)
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try:
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tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26) # insufficient fee
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else:
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assert(False)
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# Extra 0.1 BTC fee
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tx1b = CTransaction()
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tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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tx1b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
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tx1b_hex = txToHex(tx1b)
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tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
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mempool = self.nodes[0].getrawmempool()
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assert (tx1a_txid not in mempool)
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assert (tx1b_txid in mempool)
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assert_equal(tx1b_hex, self.nodes[0].getrawtransaction(tx1b_txid))
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def test_doublespend_chain(self):
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"""Doublespend of a long chain"""
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initial_nValue = 50*COIN
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tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
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prevout = tx0_outpoint
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remaining_value = initial_nValue
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chain_txids = []
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while remaining_value > 10*COIN:
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remaining_value -= 1*COIN
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tx = CTransaction()
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tx.vin = [CTxIn(prevout, nSequence=0)]
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tx.vout = [CTxOut(remaining_value, CScript([1]))]
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tx_hex = txToHex(tx)
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txid = self.nodes[0].sendrawtransaction(tx_hex, True)
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chain_txids.append(txid)
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prevout = COutPoint(int(txid, 16), 0)
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# Whether the double-spend is allowed is evaluated by including all
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# child fees - 40 BTC - so this attempt is rejected.
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dbl_tx = CTransaction()
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dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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dbl_tx.vout = [CTxOut(initial_nValue - 30*COIN, CScript([1]))]
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dbl_tx_hex = txToHex(dbl_tx)
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try:
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self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26) # insufficient fee
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else:
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assert(False) # transaction mistakenly accepted!
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# Accepted with sufficient fee
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dbl_tx = CTransaction()
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dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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dbl_tx.vout = [CTxOut(1*COIN, CScript([1]))]
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dbl_tx_hex = txToHex(dbl_tx)
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self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
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mempool = self.nodes[0].getrawmempool()
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for doublespent_txid in chain_txids:
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assert(doublespent_txid not in mempool)
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def test_doublespend_tree(self):
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"""Doublespend of a big tree of transactions"""
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initial_nValue = 50*COIN
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tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
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def branch(prevout, initial_value, max_txs, tree_width=5, fee=0.0001*COIN, _total_txs=None):
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if _total_txs is None:
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_total_txs = [0]
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if _total_txs[0] >= max_txs:
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return
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txout_value = (initial_value - fee) // tree_width
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if txout_value < fee:
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return
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vout = [CTxOut(txout_value, CScript([i+1]))
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for i in range(tree_width)]
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tx = CTransaction()
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tx.vin = [CTxIn(prevout, nSequence=0)]
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tx.vout = vout
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tx_hex = txToHex(tx)
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assert(len(tx.serialize()) < 100000)
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txid = self.nodes[0].sendrawtransaction(tx_hex, True)
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yield tx
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_total_txs[0] += 1
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txid = int(txid, 16)
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for i, txout in enumerate(tx.vout):
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for x in branch(COutPoint(txid, i), txout_value,
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max_txs,
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tree_width=tree_width, fee=fee,
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_total_txs=_total_txs):
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yield x
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fee = 0.0001*COIN
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n = MAX_REPLACEMENT_LIMIT
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tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
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assert_equal(len(tree_txs), n)
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# Attempt double-spend, will fail because too little fee paid
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dbl_tx = CTransaction()
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dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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dbl_tx.vout = [CTxOut(initial_nValue - fee*n, CScript([1]))]
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dbl_tx_hex = txToHex(dbl_tx)
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try:
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self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26) # insufficient fee
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else:
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assert(False)
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# 1 BTC fee is enough
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dbl_tx = CTransaction()
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dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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dbl_tx.vout = [CTxOut(initial_nValue - fee*n - 1*COIN, CScript([1]))]
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dbl_tx_hex = txToHex(dbl_tx)
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self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
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mempool = self.nodes[0].getrawmempool()
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for tx in tree_txs:
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tx.rehash()
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assert (tx.hash not in mempool)
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# Try again, but with more total transactions than the "max txs
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# double-spent at once" anti-DoS limit.
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for n in (MAX_REPLACEMENT_LIMIT+1, MAX_REPLACEMENT_LIMIT*2):
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fee = 0.0001*COIN
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tx0_outpoint = make_utxo(self.nodes[0], initial_nValue)
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tree_txs = list(branch(tx0_outpoint, initial_nValue, n, fee=fee))
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assert_equal(len(tree_txs), n)
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dbl_tx = CTransaction()
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dbl_tx.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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dbl_tx.vout = [CTxOut(initial_nValue - 2*fee*n, CScript([1]))]
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dbl_tx_hex = txToHex(dbl_tx)
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try:
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self.nodes[0].sendrawtransaction(dbl_tx_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26)
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assert_equal("too many potential replacements" in exp.error['message'], True)
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else:
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assert(False)
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for tx in tree_txs:
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tx.rehash()
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self.nodes[0].getrawtransaction(tx.hash)
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def test_replacement_feeperkb(self):
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"""Replacement requires fee-per-KB to be higher"""
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tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
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tx1a = CTransaction()
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tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
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tx1a_hex = txToHex(tx1a)
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tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
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# Higher fee, but the fee per KB is much lower, so the replacement is
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# rejected.
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tx1b = CTransaction()
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tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
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tx1b.vout = [CTxOut(0.001*COIN, CScript([b'a'*999000]))]
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tx1b_hex = txToHex(tx1b)
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try:
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tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26) # insufficient fee
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else:
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assert(False)
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def test_spends_of_conflicting_outputs(self):
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"""Replacements that spend conflicting tx outputs are rejected"""
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utxo1 = make_utxo(self.nodes[0], 1.2*COIN)
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utxo2 = make_utxo(self.nodes[0], 3.0*COIN)
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tx1a = CTransaction()
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tx1a.vin = [CTxIn(utxo1, nSequence=0)]
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tx1a.vout = [CTxOut(1.1*COIN, CScript([b'a']))]
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tx1a_hex = txToHex(tx1a)
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tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
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tx1a_txid = int(tx1a_txid, 16)
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# Direct spend an output of the transaction we're replacing.
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tx2 = CTransaction()
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tx2.vin = [CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0)]
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tx2.vin.append(CTxIn(COutPoint(tx1a_txid, 0), nSequence=0))
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tx2.vout = tx1a.vout
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tx2_hex = txToHex(tx2)
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try:
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tx2_txid = self.nodes[0].sendrawtransaction(tx2_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26)
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else:
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assert(False)
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# Spend tx1a's output to test the indirect case.
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tx1b = CTransaction()
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tx1b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
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tx1b.vout = [CTxOut(1.0*COIN, CScript([b'a']))]
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tx1b_hex = txToHex(tx1b)
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tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
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tx1b_txid = int(tx1b_txid, 16)
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tx2 = CTransaction()
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tx2.vin = [CTxIn(utxo1, nSequence=0), CTxIn(utxo2, nSequence=0),
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CTxIn(COutPoint(tx1b_txid, 0))]
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tx2.vout = tx1a.vout
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tx2_hex = txToHex(tx2)
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try:
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tx2_txid = self.nodes[0].sendrawtransaction(tx2_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26)
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else:
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assert(False)
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def test_new_unconfirmed_inputs(self):
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"""Replacements that add new unconfirmed inputs are rejected"""
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confirmed_utxo = make_utxo(self.nodes[0], 1.1*COIN)
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unconfirmed_utxo = make_utxo(self.nodes[0], 0.1*COIN, False)
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tx1 = CTransaction()
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tx1.vin = [CTxIn(confirmed_utxo)]
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tx1.vout = [CTxOut(1.0*COIN, CScript([b'a']))]
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tx1_hex = txToHex(tx1)
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tx1_txid = self.nodes[0].sendrawtransaction(tx1_hex, True)
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tx2 = CTransaction()
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tx2.vin = [CTxIn(confirmed_utxo), CTxIn(unconfirmed_utxo)]
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tx2.vout = tx1.vout
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tx2_hex = txToHex(tx2)
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try:
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tx2_txid = self.nodes[0].sendrawtransaction(tx2_hex, True)
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except JSONRPCException as exp:
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assert_equal(exp.error['code'], -26)
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else:
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assert(False)
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def test_too_many_replacements(self):
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"""Replacements that evict too many transactions are rejected"""
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# Try directly replacing more than MAX_REPLACEMENT_LIMIT
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# transactions
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# Start by creating a single transaction with many outputs
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initial_nValue = 10*COIN
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utxo = make_utxo(self.nodes[0], initial_nValue)
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fee = 0.0001*COIN
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split_value = int((initial_nValue-fee)/(MAX_REPLACEMENT_LIMIT+1))
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actual_fee = initial_nValue - split_value*(MAX_REPLACEMENT_LIMIT+1)
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outputs = []
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for i in range(MAX_REPLACEMENT_LIMIT+1):
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outputs.append(CTxOut(split_value, CScript([1])))
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splitting_tx = CTransaction()
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splitting_tx.vin = [CTxIn(utxo, nSequence=0)]
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splitting_tx.vout = outputs
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splitting_tx_hex = txToHex(splitting_tx)
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txid = self.nodes[0].sendrawtransaction(splitting_tx_hex, True)
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txid = int(txid, 16)
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# Now spend each of those outputs individually
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for i in range(MAX_REPLACEMENT_LIMIT+1):
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tx_i = CTransaction()
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tx_i.vin = [CTxIn(COutPoint(txid, i), nSequence=0)]
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tx_i.vout = [CTxOut(split_value-fee, CScript([b'a']))]
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tx_i_hex = txToHex(tx_i)
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self.nodes[0].sendrawtransaction(tx_i_hex, True)
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# Now create doublespend of the whole lot; should fail.
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# Need a big enough fee to cover all spending transactions and have
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# a higher fee rate
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double_spend_value = (split_value-100*fee)*(MAX_REPLACEMENT_LIMIT+1)
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inputs = []
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for i in range(MAX_REPLACEMENT_LIMIT+1):
|
||||
inputs.append(CTxIn(COutPoint(txid, i), nSequence=0))
|
||||
double_tx = CTransaction()
|
||||
double_tx.vin = inputs
|
||||
double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))]
|
||||
double_tx_hex = txToHex(double_tx)
|
||||
|
||||
try:
|
||||
self.nodes[0].sendrawtransaction(double_tx_hex, True)
|
||||
except JSONRPCException as exp:
|
||||
assert_equal(exp.error['code'], -26)
|
||||
assert_equal("too many potential replacements" in exp.error['message'], True)
|
||||
else:
|
||||
assert(False)
|
||||
|
||||
# If we remove an input, it should pass
|
||||
double_tx = CTransaction()
|
||||
double_tx.vin = inputs[0:-1]
|
||||
double_tx.vout = [CTxOut(double_spend_value, CScript([b'a']))]
|
||||
double_tx_hex = txToHex(double_tx)
|
||||
self.nodes[0].sendrawtransaction(double_tx_hex, True)
|
||||
|
||||
def test_opt_in(self):
|
||||
""" Replacing should only work if orig tx opted in """
|
||||
tx0_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
|
||||
|
||||
# Create a non-opting in transaction
|
||||
tx1a = CTransaction()
|
||||
tx1a.vin = [CTxIn(tx0_outpoint, nSequence=0xffffffff)]
|
||||
tx1a.vout = [CTxOut(1*COIN, CScript([b'a']))]
|
||||
tx1a_hex = txToHex(tx1a)
|
||||
tx1a_txid = self.nodes[0].sendrawtransaction(tx1a_hex, True)
|
||||
|
||||
# Shouldn't be able to double-spend
|
||||
tx1b = CTransaction()
|
||||
tx1b.vin = [CTxIn(tx0_outpoint, nSequence=0)]
|
||||
tx1b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
|
||||
tx1b_hex = txToHex(tx1b)
|
||||
|
||||
try:
|
||||
tx1b_txid = self.nodes[0].sendrawtransaction(tx1b_hex, True)
|
||||
except JSONRPCException as exp:
|
||||
assert_equal(exp.error['code'], -26)
|
||||
else:
|
||||
print tx1b_txid
|
||||
assert(False)
|
||||
|
||||
tx1_outpoint = make_utxo(self.nodes[0], 1.1*COIN)
|
||||
|
||||
# Create a different non-opting in transaction
|
||||
tx2a = CTransaction()
|
||||
tx2a.vin = [CTxIn(tx1_outpoint, nSequence=0xfffffffe)]
|
||||
tx2a.vout = [CTxOut(1*COIN, CScript([b'a']))]
|
||||
tx2a_hex = txToHex(tx2a)
|
||||
tx2a_txid = self.nodes[0].sendrawtransaction(tx2a_hex, True)
|
||||
|
||||
# Still shouldn't be able to double-spend
|
||||
tx2b = CTransaction()
|
||||
tx2b.vin = [CTxIn(tx1_outpoint, nSequence=0)]
|
||||
tx2b.vout = [CTxOut(0.9*COIN, CScript([b'b']))]
|
||||
tx2b_hex = txToHex(tx2b)
|
||||
|
||||
try:
|
||||
tx2b_txid = self.nodes[0].sendrawtransaction(tx2b_hex, True)
|
||||
except JSONRPCException as exp:
|
||||
assert_equal(exp.error['code'], -26)
|
||||
else:
|
||||
assert(False)
|
||||
|
||||
# Now create a new transaction that spends from tx1a and tx2a
|
||||
# opt-in on one of the inputs
|
||||
# Transaction should be replaceable on either input
|
||||
|
||||
tx1a_txid = int(tx1a_txid, 16)
|
||||
tx2a_txid = int(tx2a_txid, 16)
|
||||
|
||||
tx3a = CTransaction()
|
||||
tx3a.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0xffffffff),
|
||||
CTxIn(COutPoint(tx2a_txid, 0), nSequence=0xfffffffd)]
|
||||
tx3a.vout = [CTxOut(0.9*COIN, CScript([b'c'])), CTxOut(0.9*COIN, CScript([b'd']))]
|
||||
tx3a_hex = txToHex(tx3a)
|
||||
|
||||
self.nodes[0].sendrawtransaction(tx3a_hex, True)
|
||||
|
||||
tx3b = CTransaction()
|
||||
tx3b.vin = [CTxIn(COutPoint(tx1a_txid, 0), nSequence=0)]
|
||||
tx3b.vout = [CTxOut(0.5*COIN, CScript([b'e']))]
|
||||
tx3b_hex = txToHex(tx3b)
|
||||
|
||||
tx3c = CTransaction()
|
||||
tx3c.vin = [CTxIn(COutPoint(tx2a_txid, 0), nSequence=0)]
|
||||
tx3c.vout = [CTxOut(0.5*COIN, CScript([b'f']))]
|
||||
tx3c_hex = txToHex(tx3c)
|
||||
|
||||
self.nodes[0].sendrawtransaction(tx3b_hex, True)
|
||||
# If tx3b was accepted, tx3c won't look like a replacement,
|
||||
# but make sure it is accepted anyway
|
||||
self.nodes[0].sendrawtransaction(tx3c_hex, True)
|
||||
|
||||
if __name__ == '__main__':
|
||||
ReplaceByFeeTest().main()
|
||||
Loading…
Reference in New Issue
Block a user