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Use the noexcept specifier (C++11) instead of deprecated throw()
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@ -26,13 +26,13 @@ struct secure_allocator : public std::allocator<T> {
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typedef typename base::reference reference;
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typedef typename base::const_reference const_reference;
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typedef typename base::value_type value_type;
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secure_allocator() throw() {}
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secure_allocator(const secure_allocator& a) throw() : base(a) {}
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secure_allocator() noexcept {}
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secure_allocator(const secure_allocator& a) noexcept : base(a) {}
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template <typename U>
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secure_allocator(const secure_allocator<U>& a) throw() : base(a)
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secure_allocator(const secure_allocator<U>& a) noexcept : base(a)
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{
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}
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~secure_allocator() throw() {}
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~secure_allocator() noexcept {}
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template <typename _Other>
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struct rebind {
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typedef secure_allocator<_Other> other;
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@ -22,13 +22,13 @@ struct zero_after_free_allocator : public std::allocator<T> {
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typedef typename base::reference reference;
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typedef typename base::const_reference const_reference;
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typedef typename base::value_type value_type;
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zero_after_free_allocator() throw() {}
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zero_after_free_allocator(const zero_after_free_allocator& a) throw() : base(a) {}
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zero_after_free_allocator() noexcept {}
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zero_after_free_allocator(const zero_after_free_allocator& a) noexcept : base(a) {}
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template <typename U>
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zero_after_free_allocator(const zero_after_free_allocator<U>& a) throw() : base(a)
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zero_after_free_allocator(const zero_after_free_allocator<U>& a) noexcept : base(a)
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{
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}
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~zero_after_free_allocator() throw() {}
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~zero_after_free_allocator() noexcept {}
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template <typename _Other>
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struct rebind {
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typedef zero_after_free_allocator<_Other> other;
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