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Merge bitcoin/bitcoin#23515: test: Return the largest utxo in MiniWallet.get_utxo
fa62207737657e76ba45d5bf826fc0ccac658df6 test: Return the largest utxo in MiniWallet.get_utxo (MarcoFalke) Pull request description: This is for consistency with the `send_self_transfer` method. Also, remove the feature that the change of the last transfer can be retrieved via `get_utxo`. This can trivially and clearer be achieved by simply passing the txid of the transfer. Also, this fixes the bug in `feature_txindex_compatibility` in current master after a silent merge conflict. Fixes #23514 Top commit has no ACKs. Tree-SHA512: edd066d372aaa72b4e0fc7526f84931c8d1f6d14f53678cb7832bc8e3d211f44b90ec9c59b7d915ef24acc63a36e7d66c8d3b7598355bd490ac637ed3bcc3dff
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@ -54,7 +54,7 @@ class MerkleBlockTest(BitcoinTestFramework):
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assert_equal(self.nodes[0].verifytxoutproof(self.nodes[0].gettxoutproof([txid1, txid2])), txlist)
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assert_equal(self.nodes[0].verifytxoutproof(self.nodes[0].gettxoutproof([txid1, txid2], blockhash)), txlist)
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txin_spent = miniwallet.get_utxo() # Get the change from txid2
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txin_spent = miniwallet.get_utxo(txid=txid2) # Get the change from txid2
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tx3 = miniwallet.send_self_transfer(from_node=self.nodes[0], utxo_to_spend=txin_spent)
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txid3 = tx3['txid']
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self.generate(self.nodes[0], 1)
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@ -135,10 +135,9 @@ class MiniWallet:
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Args:
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txid: get the first utxo we find from a specific transaction
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Note: Can be used to get the change output immediately after a send_self_transfer
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"""
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index = -1 # by default the last utxo
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self._utxos = sorted(self._utxos, key=lambda k: (k['value'], -k['height'])) # Put the largest utxo last
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if txid:
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utxo = next(filter(lambda utxo: txid == utxo['txid'], self._utxos))
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index = self._utxos.index(utxo)
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@ -155,8 +154,7 @@ class MiniWallet:
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def create_self_transfer(self, *, fee_rate=Decimal("0.003"), from_node, utxo_to_spend=None, mempool_valid=True, locktime=0, sequence=0):
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"""Create and return a tx with the specified fee_rate. Fee may be exact or at most one satoshi higher than needed."""
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self._utxos = sorted(self._utxos, key=lambda k: (k['value'], -k['height']))
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utxo_to_spend = utxo_to_spend or self._utxos.pop() # Pick the largest utxo (if none provided) and hope it covers the fee
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utxo_to_spend = utxo_to_spend or self.get_utxo()
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if self._priv_key is None:
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vsize = Decimal(85) # anyone-can-spend
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else:
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