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Improve robustness of DER recoding code
Add some defensive programming on top of #5634. This copies the respective OpenSSL code in ECDSA_verify in OpenSSL pre-1.0.1k (e.g. https://github.com/openssl/openssl/blob/OpenSSL_1_0_1j/crypto/ecdsa/ecs_vrf.c#L89) more closely. As reported by @sergiodemianlerner.
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@ -124,7 +124,18 @@ bool CECKey::Verify(const uint256 &hash, const std::vector<unsigned char>& vchSi
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unsigned char *norm_der = NULL;
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unsigned char *norm_der = NULL;
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ECDSA_SIG *norm_sig = ECDSA_SIG_new();
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ECDSA_SIG *norm_sig = ECDSA_SIG_new();
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const unsigned char* sigptr = &vchSig[0];
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const unsigned char* sigptr = &vchSig[0];
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d2i_ECDSA_SIG(&norm_sig, &sigptr, vchSig.size());
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assert(norm_sig);
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if (d2i_ECDSA_SIG(&norm_sig, &sigptr, vchSig.size()) == NULL)
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{
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/* As of OpenSSL 1.0.0p d2i_ECDSA_SIG frees and nulls the pointer on
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* error. But OpenSSL's own use of this function redundantly frees the
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* result. As ECDSA_SIG_free(NULL) is a no-op, and in the absence of a
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* clear contract for the function behaving the same way is more
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* conservative.
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*/
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ECDSA_SIG_free(norm_sig);
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return false;
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}
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int derlen = i2d_ECDSA_SIG(norm_sig, &norm_der);
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int derlen = i2d_ECDSA_SIG(norm_sig, &norm_der);
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ECDSA_SIG_free(norm_sig);
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ECDSA_SIG_free(norm_sig);
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if (derlen <= 0)
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if (derlen <= 0)
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