#!/usr/bin/env python3 # Copyright (c) 2018-2020 The Bitcoin Core developers # Distributed under the MIT software license, see the accompanying # file COPYING or http://www.opensource.org/licenses/mit-license.php. """Test wallet group functionality.""" from test_framework.blocktools import COINBASE_MATURITY from test_framework.test_framework import BitcoinTestFramework from test_framework.messages import ( tx_from_hex, ) from test_framework.util import ( assert_approx, assert_equal, ) class WalletGroupTest(BitcoinTestFramework): def set_test_params(self): self.setup_clean_chain = True self.num_nodes = 5 self.extra_args = [ [], [], ["-avoidpartialspends"], ["-maxapsfee=0.00000293"], ["-maxapsfee=0.00000294"], ] self.rpc_timeout = 480 self.supports_cli = False def skip_test_if_missing_module(self): self.skip_if_no_wallet() def run_test(self): # Mine some coins self.nodes[0].generate(COINBASE_MATURITY + 10) # Get some addresses from the two nodes addr1 = [self.nodes[1].getnewaddress() for _ in range(3)] addr2 = [self.nodes[2].getnewaddress() for _ in range(3)] addrs = addr1 + addr2 # Send 1 + 0.5 coin to each address [self.nodes[0].sendtoaddress(addr, 1.0) for addr in addrs] [self.nodes[0].sendtoaddress(addr, 0.5) for addr in addrs] self.nodes[0].generate(1) self.sync_all() # For each node, send 0.2 coins back to 0; # - node[1] should pick one 0.5 UTXO and leave the rest # - node[2] should pick one (1.0 + 0.5) UTXO group corresponding to a # given address, and leave the rest txid1 = self.nodes[1].sendtoaddress(self.nodes[0].getnewaddress(), 0.2) tx1 = self.nodes[1].getrawtransaction(txid1, True) # txid1 should have 1 input and 2 outputs assert_equal(1, len(tx1["vin"])) assert_equal(2, len(tx1["vout"])) # one output should be 0.2, the other should be ~0.3 v = [vout["value"] for vout in tx1["vout"]] v.sort() assert_approx(v[0], vexp=0.2, vspan=0.0001) assert_approx(v[1], vexp=0.3, vspan=0.0001) txid2 = self.nodes[2].sendtoaddress(self.nodes[0].getnewaddress(), 0.2) tx2 = self.nodes[2].getrawtransaction(txid2, True) # txid2 should have 2 inputs and 2 outputs assert_equal(2, len(tx2["vin"])) assert_equal(2, len(tx2["vout"])) # one output should be 0.2, the other should be ~1.3 v = [vout["value"] for vout in tx2["vout"]] v.sort() assert_approx(v[0], vexp=0.2, vspan=0.0001) assert_approx(v[1], vexp=1.3, vspan=0.0001) # Test 'avoid partial if warranted, even if disabled' self.sync_all() self.nodes[0].generate(1) # Nodes 1-2 now have confirmed UTXOs (letters denote destinations): # Node #1: Node #2: # - A 1.0 - D0 1.0 # - B0 1.0 - D1 0.5 # - B1 0.5 - E0 1.0 # - C0 1.0 - E1 0.5 # - C1 0.5 - F ~1.3 # - D ~0.3 assert_approx(self.nodes[1].getbalance(), vexp=4.3, vspan=0.0001) assert_approx(self.nodes[2].getbalance(), vexp=4.3, vspan=0.0001) # Sending 1.4 btc should pick one 1.0 + one more. For node #1, # this could be (A / B0 / C0) + (B1 / C1 / D). We ensure that it is # B0 + B1 or C0 + C1, because this avoids partial spends while not being # detrimental to transaction cost txid3 = self.nodes[1].sendtoaddress(self.nodes[0].getnewaddress(), 1.4) tx3 = self.nodes[1].getrawtransaction(txid3, True) # tx3 should have 2 inputs and 2 outputs assert_equal(2, len(tx3["vin"])) assert_equal(2, len(tx3["vout"])) # the accumulated value should be 1.5, so the outputs should be # ~0.1 and 1.4 and should come from the same destination values = [vout["value"] for vout in tx3["vout"]] values.sort() assert_approx(values[0], vexp=0.1, vspan=0.0001) assert_approx(values[1], vexp=1.4, vspan=0.0001) input_txids = [vin["txid"] for vin in tx3["vin"]] input_addrs = [self.nodes[1].gettransaction(txid)['details'][0]['address'] for txid in input_txids] assert_equal(input_addrs[0], input_addrs[1]) # Node 2 enforces avoidpartialspends so needs no checking here # Test wallet option maxapsfee with Node 3 addr_aps = self.nodes[3].getnewaddress() self.nodes[0].sendtoaddress(addr_aps, 1.0) self.nodes[0].sendtoaddress(addr_aps, 1.0) self.nodes[0].generate(1) self.sync_all() with self.nodes[3].assert_debug_log(['Fee non-grouped = 225, grouped = 372, using grouped']): txid4 = self.nodes[3].sendtoaddress(self.nodes[0].getnewaddress(), 0.1) tx4 = self.nodes[3].getrawtransaction(txid4, True) # tx4 should have 2 inputs and 2 outputs although one output would # have been enough and the transaction caused higher fees assert_equal(2, len(tx4["vin"])) assert_equal(2, len(tx4["vout"])) addr_aps2 = self.nodes[3].getnewaddress() [self.nodes[0].sendtoaddress(addr_aps2, 1.0) for _ in range(5)] self.nodes[0].generate(1) self.sync_all() with self.nodes[3].assert_debug_log(['Fee non-grouped = 519, grouped = 813, using non-grouped']): txid5 = self.nodes[3].sendtoaddress(self.nodes[0].getnewaddress(), 2.95) tx5 = self.nodes[3].getrawtransaction(txid5, True) # tx5 should have 3 inputs (1.0, 1.0, 1.0) and 2 outputs assert_equal(3, len(tx5["vin"])) assert_equal(2, len(tx5["vout"])) # Test wallet option maxapsfee with node 4, which sets maxapsfee # 1 sat higher, crossing the threshold from non-grouped to grouped. addr_aps3 = self.nodes[4].getnewaddress() [self.nodes[0].sendtoaddress(addr_aps3, 1.0) for _ in range(5)] self.nodes[0].generate(1) self.sync_all() with self.nodes[4].assert_debug_log(['Fee non-grouped = 519, grouped = 813, using grouped']): txid6 = self.nodes[4].sendtoaddress(self.nodes[0].getnewaddress(), 2.95) tx6 = self.nodes[4].getrawtransaction(txid6, True) # tx6 should have 5 inputs and 2 outputs assert_equal(5, len(tx6["vin"])) assert_equal(2, len(tx6["vout"])) # Empty out node2's wallet self.nodes[2].sendtoaddress(address=self.nodes[0].getnewaddress(), amount=self.nodes[2].getbalance(), subtractfeefromamount=True) self.sync_all() self.nodes[0].generate(1) # Fill node2's wallet with 10000 outputs corresponding to the same # scriptPubKey for _ in range(5): raw_tx = self.nodes[0].createrawtransaction([{"txid":"0"*64, "vout":0}], [{addr2[0]: 0.05}]) tx = tx_from_hex(raw_tx) tx.vin = [] tx.vout = [tx.vout[0]] * 2000 funded_tx = self.nodes[0].fundrawtransaction(tx.serialize().hex()) signed_tx = self.nodes[0].signrawtransactionwithwallet(funded_tx['hex']) self.nodes[0].sendrawtransaction(signed_tx['hex']) self.nodes[0].generate(1) self.sync_all() # Check that we can create a transaction that only requires ~100 of our # utxos, without pulling in all outputs and creating a transaction that # is way too big. assert self.nodes[2].sendtoaddress(address=addr2[0], amount=5) if __name__ == '__main__': WalletGroupTest().main()