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870824e919
Breaking API serves no purpose other than to be incompatible with older versions and other implementations that do support priority
245 lines
10 KiB
Python
Executable File
245 lines
10 KiB
Python
Executable File
#!/usr/bin/env python3
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# Copyright (c) 2014-2016 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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"""Test descendant package tracking code."""
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import *
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from test_framework.mininode import COIN
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MAX_ANCESTORS = 25
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MAX_DESCENDANTS = 25
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class MempoolPackagesTest(BitcoinTestFramework):
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def __init__(self):
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super().__init__()
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self.num_nodes = 2
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self.setup_clean_chain = False
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self.extra_args = [["-maxorphantx=1000"], ["-maxorphantx=1000", "-limitancestorcount=5"]]
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# Build a transaction that spends parent_txid:vout
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# Return amount sent
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def chain_transaction(self, node, parent_txid, vout, value, fee, num_outputs):
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send_value = satoshi_round((value - fee)/num_outputs)
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inputs = [ {'txid' : parent_txid, 'vout' : vout} ]
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outputs = {}
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for i in range(num_outputs):
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outputs[node.getnewaddress()] = send_value
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rawtx = node.createrawtransaction(inputs, outputs)
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signedtx = node.signrawtransaction(rawtx)
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txid = node.sendrawtransaction(signedtx['hex'])
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fulltx = node.getrawtransaction(txid, 1)
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assert(len(fulltx['vout']) == num_outputs) # make sure we didn't generate a change output
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return (txid, send_value)
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def run_test(self):
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''' Mine some blocks and have them mature. '''
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self.nodes[0].generate(101)
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utxo = self.nodes[0].listunspent(10)
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txid = utxo[0]['txid']
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vout = utxo[0]['vout']
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value = utxo[0]['amount']
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fee = Decimal("0.0001")
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# MAX_ANCESTORS transactions off a confirmed tx should be fine
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chain = []
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for i in range(MAX_ANCESTORS):
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, 0, value, fee, 1)
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value = sent_value
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chain.append(txid)
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# Check mempool has MAX_ANCESTORS transactions in it, and descendant
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# count and fees should look correct
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mempool = self.nodes[0].getrawmempool(True)
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assert_equal(len(mempool), MAX_ANCESTORS)
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descendant_count = 1
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descendant_fees = 0
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descendant_size = 0
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descendants = []
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ancestors = list(chain)
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for x in reversed(chain):
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# Check that getmempoolentry is consistent with getrawmempool
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entry = self.nodes[0].getmempoolentry(x)
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assert_equal(entry, mempool[x])
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# Check that the descendant calculations are correct
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assert_equal(mempool[x]['descendantcount'], descendant_count)
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descendant_fees += mempool[x]['fee']
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assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee'])
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assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN)
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descendant_size += mempool[x]['size']
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assert_equal(mempool[x]['descendantsize'], descendant_size)
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descendant_count += 1
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# Check that getmempooldescendants is correct
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assert_equal(sorted(descendants), sorted(self.nodes[0].getmempooldescendants(x)))
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descendants.append(x)
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# Check that getmempoolancestors is correct
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ancestors.remove(x)
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assert_equal(sorted(ancestors), sorted(self.nodes[0].getmempoolancestors(x)))
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# Check that getmempoolancestors/getmempooldescendants correctly handle verbose=true
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v_ancestors = self.nodes[0].getmempoolancestors(chain[-1], True)
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assert_equal(len(v_ancestors), len(chain)-1)
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for x in v_ancestors.keys():
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assert_equal(mempool[x], v_ancestors[x])
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assert(chain[-1] not in v_ancestors.keys())
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v_descendants = self.nodes[0].getmempooldescendants(chain[0], True)
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assert_equal(len(v_descendants), len(chain)-1)
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for x in v_descendants.keys():
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assert_equal(mempool[x], v_descendants[x])
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assert(chain[0] not in v_descendants.keys())
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# Check that ancestor modified fees includes fee deltas from
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# prioritisetransaction
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self.nodes[0].prioritisetransaction(txid=chain[0], fee_delta=1000)
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mempool = self.nodes[0].getrawmempool(True)
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ancestor_fees = 0
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for x in chain:
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ancestor_fees += mempool[x]['fee']
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assert_equal(mempool[x]['ancestorfees'], ancestor_fees * COIN + 1000)
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# Undo the prioritisetransaction for later tests
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self.nodes[0].prioritisetransaction(txid=chain[0], fee_delta=-1000)
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# Check that descendant modified fees includes fee deltas from
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# prioritisetransaction
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self.nodes[0].prioritisetransaction(txid=chain[-1], fee_delta=1000)
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mempool = self.nodes[0].getrawmempool(True)
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descendant_fees = 0
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for x in reversed(chain):
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descendant_fees += mempool[x]['fee']
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assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 1000)
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# Adding one more transaction on to the chain should fail.
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assert_raises_jsonrpc(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], txid, vout, value, fee, 1)
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# Check that prioritising a tx before it's added to the mempool works
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# First clear the mempool by mining a block.
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self.nodes[0].generate(1)
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sync_blocks(self.nodes)
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assert_equal(len(self.nodes[0].getrawmempool()), 0)
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# Prioritise a transaction that has been mined, then add it back to the
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# mempool by using invalidateblock.
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self.nodes[0].prioritisetransaction(txid=chain[-1], fee_delta=2000)
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
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# Keep node1's tip synced with node0
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self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
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# Now check that the transaction is in the mempool, with the right modified fee
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mempool = self.nodes[0].getrawmempool(True)
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descendant_fees = 0
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for x in reversed(chain):
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descendant_fees += mempool[x]['fee']
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if (x == chain[-1]):
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assert_equal(mempool[x]['modifiedfee'], mempool[x]['fee']+satoshi_round(0.00002))
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assert_equal(mempool[x]['descendantfees'], descendant_fees * COIN + 2000)
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# TODO: check that node1's mempool is as expected
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# TODO: test ancestor size limits
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# Now test descendant chain limits
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txid = utxo[1]['txid']
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value = utxo[1]['amount']
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vout = utxo[1]['vout']
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transaction_package = []
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# First create one parent tx with 10 children
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 10)
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parent_transaction = txid
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for i in range(10):
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transaction_package.append({'txid': txid, 'vout': i, 'amount': sent_value})
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# Sign and send up to MAX_DESCENDANT transactions chained off the parent tx
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for i in range(MAX_DESCENDANTS - 1):
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utxo = transaction_package.pop(0)
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(txid, sent_value) = self.chain_transaction(self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
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for j in range(10):
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transaction_package.append({'txid': txid, 'vout': j, 'amount': sent_value})
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mempool = self.nodes[0].getrawmempool(True)
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assert_equal(mempool[parent_transaction]['descendantcount'], MAX_DESCENDANTS)
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# Sending one more chained transaction will fail
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utxo = transaction_package.pop(0)
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assert_raises_jsonrpc(-26, "too-long-mempool-chain", self.chain_transaction, self.nodes[0], utxo['txid'], utxo['vout'], utxo['amount'], fee, 10)
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# TODO: check that node1's mempool is as expected
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# TODO: test descendant size limits
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# Test reorg handling
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# First, the basics:
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self.nodes[0].generate(1)
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sync_blocks(self.nodes)
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self.nodes[1].invalidateblock(self.nodes[0].getbestblockhash())
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self.nodes[1].reconsiderblock(self.nodes[0].getbestblockhash())
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# Now test the case where node1 has a transaction T in its mempool that
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# depends on transactions A and B which are in a mined block, and the
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# block containing A and B is disconnected, AND B is not accepted back
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# into node1's mempool because its ancestor count is too high.
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# Create 8 transactions, like so:
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# Tx0 -> Tx1 (vout0)
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# \--> Tx2 (vout1) -> Tx3 -> Tx4 -> Tx5 -> Tx6 -> Tx7
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#
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# Mine them in the next block, then generate a new tx8 that spends
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# Tx1 and Tx7, and add to node1's mempool, then disconnect the
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# last block.
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# Create tx0 with 2 outputs
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utxo = self.nodes[0].listunspent()
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txid = utxo[0]['txid']
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value = utxo[0]['amount']
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vout = utxo[0]['vout']
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send_value = satoshi_round((value - fee)/2)
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inputs = [ {'txid' : txid, 'vout' : vout} ]
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outputs = {}
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for i in range(2):
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outputs[self.nodes[0].getnewaddress()] = send_value
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rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
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signedtx = self.nodes[0].signrawtransaction(rawtx)
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txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
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tx0_id = txid
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value = send_value
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# Create tx1
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(tx1_id, tx1_value) = self.chain_transaction(self.nodes[0], tx0_id, 0, value, fee, 1)
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# Create tx2-7
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vout = 1
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txid = tx0_id
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for i in range(6):
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(txid, sent_value) = self.chain_transaction(self.nodes[0], txid, vout, value, fee, 1)
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vout = 0
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value = sent_value
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# Mine these in a block
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self.nodes[0].generate(1)
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self.sync_all()
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# Now generate tx8, with a big fee
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inputs = [ {'txid' : tx1_id, 'vout': 0}, {'txid' : txid, 'vout': 0} ]
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outputs = { self.nodes[0].getnewaddress() : send_value + value - 4*fee }
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rawtx = self.nodes[0].createrawtransaction(inputs, outputs)
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signedtx = self.nodes[0].signrawtransaction(rawtx)
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txid = self.nodes[0].sendrawtransaction(signedtx['hex'])
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sync_mempools(self.nodes)
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# Now try to disconnect the tip on each node...
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self.nodes[1].invalidateblock(self.nodes[1].getbestblockhash())
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self.nodes[0].invalidateblock(self.nodes[0].getbestblockhash())
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sync_blocks(self.nodes)
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if __name__ == '__main__':
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MempoolPackagesTest().main()
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