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a6c2c3a6d2
fa489011d9202d61463dbc426041c867f2670438 test: Remove raw-tx byte juggling in mempool_reorg (MarcoFalke)
Pull request description:
ACKs for top commit:
robot-visions:
ACK fa489011d9202d61463dbc426041c867f2670438
Tree-SHA512: 2ae537a5b34e48d2954ba02d9e050ae1a99043080266d5decca3f983b13bc3ddcbee1f3f3c7457e16ee76ea17b9ce08cac2e3205cf46b5e3c3e4ca5f758f00de
112 lines
4.9 KiB
Python
Executable File
112 lines
4.9 KiB
Python
Executable File
#!/usr/bin/env python3
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# Copyright (c) 2014-2016 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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"""Test mempool re-org scenarios.
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Test re-org scenarios with a mempool that contains transactions
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that spend (directly or indirectly) coinbase transactions.
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"""
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from test_framework.blocktools import create_raw_transaction
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import assert_equal, assert_raises_rpc_error
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class MempoolCoinbaseTest(BitcoinTestFramework):
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def set_test_params(self):
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self.num_nodes = 2
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self.extra_args = [
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[
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'-whitelist=noban@127.0.0.1', # immediate tx relay
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],
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[]
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]
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def skip_test_if_missing_module(self):
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self.skip_if_no_wallet()
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def run_test(self):
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# Start with a 200 block chain
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assert_equal(self.nodes[0].getblockcount(), 200)
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# Mine four blocks. After this, nodes[0] blocks
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# 101, 102, and 103 are spend-able.
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new_blocks = self.nodes[1].generate(4)
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self.sync_all()
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node0_address = self.nodes[0].getnewaddress()
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node1_address = self.nodes[1].getnewaddress()
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# Three scenarios for re-orging coinbase spends in the memory pool:
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# 1. Direct coinbase spend : spend_101
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# 2. Indirect (coinbase spend in chain, child in mempool) : spend_102 and spend_102_1
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# 3. Indirect (coinbase and child both in chain) : spend_103 and spend_103_1
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# Use invalidatblock to make all of the above coinbase spends invalid (immature coinbase),
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# and make sure the mempool code behaves correctly.
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b = [self.nodes[0].getblockhash(n) for n in range(101, 105)]
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coinbase_txids = [self.nodes[0].getblock(h)['tx'][0] for h in b]
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spend_101_raw = create_raw_transaction(self.nodes[0], coinbase_txids[1], node1_address, amount=499.99)
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spend_102_raw = create_raw_transaction(self.nodes[0], coinbase_txids[2], node0_address, amount=499.99)
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spend_103_raw = create_raw_transaction(self.nodes[0], coinbase_txids[3], node0_address, amount=499.99)
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# Create a transaction which is time-locked to two blocks in the future
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timelock_tx = self.nodes[0].createrawtransaction(
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inputs=[{
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"txid": coinbase_txids[0],
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"vout": 0,
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}],
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outputs={node0_address: 499.99},
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locktime=self.nodes[0].getblockcount() + 2,
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)
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timelock_tx = self.nodes[0].signrawtransactionwithwallet(timelock_tx)["hex"]
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# This will raise an exception because the timelock transaction is too immature to spend
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assert_raises_rpc_error(-26, "non-final", self.nodes[0].sendrawtransaction, timelock_tx)
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# Broadcast and mine spend_102 and 103:
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spend_102_id = self.nodes[0].sendrawtransaction(spend_102_raw)
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spend_103_id = self.nodes[0].sendrawtransaction(spend_103_raw)
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self.nodes[0].generate(1)
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# Time-locked transaction is still too immature to spend
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assert_raises_rpc_error(-26, 'non-final', self.nodes[0].sendrawtransaction, timelock_tx)
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# Create 102_1 and 103_1:
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spend_102_1_raw = create_raw_transaction(self.nodes[0], spend_102_id, node1_address, amount=499.98)
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spend_103_1_raw = create_raw_transaction(self.nodes[0], spend_103_id, node1_address, amount=499.98)
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# Broadcast and mine 103_1:
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spend_103_1_id = self.nodes[0].sendrawtransaction(spend_103_1_raw)
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last_block = self.nodes[0].generate(1)
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# Sync blocks, so that peer 1 gets the block before timelock_tx
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# Otherwise, peer 1 would put the timelock_tx in recentRejects
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self.sync_all()
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# Time-locked transaction can now be spent
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timelock_tx_id = self.nodes[0].sendrawtransaction(timelock_tx)
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# ... now put spend_101 and spend_102_1 in memory pools:
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spend_101_id = self.nodes[0].sendrawtransaction(spend_101_raw)
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spend_102_1_id = self.nodes[0].sendrawtransaction(spend_102_1_raw)
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assert_equal(set(self.nodes[0].getrawmempool()), {spend_101_id, spend_102_1_id, timelock_tx_id})
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self.sync_all()
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for node in self.nodes:
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node.invalidateblock(last_block[0])
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# Time-locked transaction is now too immature and has been removed from the mempool
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# spend_103_1 has been re-orged out of the chain and is back in the mempool
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assert_equal(set(self.nodes[0].getrawmempool()), {spend_101_id, spend_102_1_id, spend_103_1_id})
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# Use invalidateblock to re-org back and make all those coinbase spends
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# immature/invalid:
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for node in self.nodes:
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node.invalidateblock(new_blocks[0])
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# mempool should be empty.
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assert_equal(set(self.nodes[0].getrawmempool()), set())
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self.sync_all()
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if __name__ == '__main__':
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MempoolCoinbaseTest().main()
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