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0bbd8bfab6
3fd7e76f6d [tests] Move deterministic address import to setup_nodes (John Newbery) Pull request description: This requires a small changes to a few tests, but means that deterministic addresses will always be imported (unless setup_nodes behaviour is explicitly overridden). Tidies up the way we import deterministic addresses, requested in review comment here: https://github.com/bitcoin/bitcoin/pull/14468#discussion_r225594586. Tree-SHA512: 2b32edf500e286c463398487ab1153116a1dc90f64a53614716373311abdc83d8a251fdd8f42d1146b56e308664deaf62952113f66e98bc37f23968096d1a961
249 lines
11 KiB
Python
Executable File
249 lines
11 KiB
Python
Executable File
#!/usr/bin/env python3
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# Copyright (c) 2014-2016 The Bitcoin Core developers
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# Distributed under the MIT software license, see the accompanying
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# file COPYING or http://www.opensource.org/licenses/mit-license.php.
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"""Test fee estimation code."""
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from decimal import Decimal
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import random
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from test_framework.messages import CTransaction, CTxIn, CTxOut, COutPoint, ToHex, COIN
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from test_framework.script import CScript, OP_1, OP_DROP, OP_2, OP_HASH160, OP_EQUAL, hash160, OP_TRUE
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from test_framework.test_framework import BitcoinTestFramework
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from test_framework.util import (
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assert_equal,
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assert_greater_than,
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assert_greater_than_or_equal,
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connect_nodes,
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satoshi_round,
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)
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# Construct 2 trivial P2SH's and the ScriptSigs that spend them
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# So we can create many transactions without needing to spend
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# time signing.
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REDEEM_SCRIPT_1 = CScript([OP_1, OP_DROP])
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REDEEM_SCRIPT_2 = CScript([OP_2, OP_DROP])
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P2SH_1 = CScript([OP_HASH160, hash160(REDEEM_SCRIPT_1), OP_EQUAL])
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P2SH_2 = CScript([OP_HASH160, hash160(REDEEM_SCRIPT_2), OP_EQUAL])
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# Associated ScriptSig's to spend satisfy P2SH_1 and P2SH_2
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SCRIPT_SIG = [CScript([OP_TRUE, REDEEM_SCRIPT_1]), CScript([OP_TRUE, REDEEM_SCRIPT_2])]
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def small_txpuzzle_randfee(from_node, conflist, unconflist, amount, min_fee, fee_increment):
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"""Create and send a transaction with a random fee.
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The transaction pays to a trivial P2SH script, and assumes that its inputs
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are of the same form.
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The function takes a list of confirmed outputs and unconfirmed outputs
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and attempts to use the confirmed list first for its inputs.
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It adds the newly created outputs to the unconfirmed list.
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Returns (raw transaction, fee)."""
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# It's best to exponentially distribute our random fees
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# because the buckets are exponentially spaced.
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# Exponentially distributed from 1-128 * fee_increment
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rand_fee = float(fee_increment) * (1.1892 ** random.randint(0, 28))
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# Total fee ranges from min_fee to min_fee + 127*fee_increment
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fee = min_fee - fee_increment + satoshi_round(rand_fee)
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tx = CTransaction()
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total_in = Decimal("0.00000000")
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while total_in <= (amount + fee) and len(conflist) > 0:
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t = conflist.pop(0)
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total_in += t["amount"]
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tx.vin.append(CTxIn(COutPoint(int(t["txid"], 16), t["vout"]), b""))
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if total_in <= amount + fee:
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while total_in <= (amount + fee) and len(unconflist) > 0:
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t = unconflist.pop(0)
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total_in += t["amount"]
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tx.vin.append(CTxIn(COutPoint(int(t["txid"], 16), t["vout"]), b""))
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if total_in <= amount + fee:
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raise RuntimeError("Insufficient funds: need %d, have %d" % (amount + fee, total_in))
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tx.vout.append(CTxOut(int((total_in - amount - fee) * COIN), P2SH_1))
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tx.vout.append(CTxOut(int(amount * COIN), P2SH_2))
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# These transactions don't need to be signed, but we still have to insert
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# the ScriptSig that will satisfy the ScriptPubKey.
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for inp in tx.vin:
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inp.scriptSig = SCRIPT_SIG[inp.prevout.n]
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txid = from_node.sendrawtransaction(hexstring=ToHex(tx), maxfeerate=0)
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unconflist.append({"txid": txid, "vout": 0, "amount": total_in - amount - fee})
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unconflist.append({"txid": txid, "vout": 1, "amount": amount})
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return (ToHex(tx), fee)
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def split_inputs(from_node, txins, txouts, initial_split=False):
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"""Generate a lot of inputs so we can generate a ton of transactions.
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This function takes an input from txins, and creates and sends a transaction
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which splits the value into 2 outputs which are appended to txouts.
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Previously this was designed to be small inputs so they wouldn't have
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a high coin age when the notion of priority still existed."""
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prevtxout = txins.pop()
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tx = CTransaction()
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tx.vin.append(CTxIn(COutPoint(int(prevtxout["txid"], 16), prevtxout["vout"]), b""))
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half_change = satoshi_round(prevtxout["amount"] / 2)
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rem_change = prevtxout["amount"] - half_change - Decimal("0.00001000")
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tx.vout.append(CTxOut(int(half_change * COIN), P2SH_1))
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tx.vout.append(CTxOut(int(rem_change * COIN), P2SH_2))
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# If this is the initial split we actually need to sign the transaction
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# Otherwise we just need to insert the proper ScriptSig
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if (initial_split):
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completetx = from_node.signrawtransactionwithwallet(ToHex(tx))["hex"]
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else:
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tx.vin[0].scriptSig = SCRIPT_SIG[prevtxout["vout"]]
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completetx = ToHex(tx)
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txid = from_node.sendrawtransaction(hexstring=completetx, maxfeerate=0)
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txouts.append({"txid": txid, "vout": 0, "amount": half_change})
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txouts.append({"txid": txid, "vout": 1, "amount": rem_change})
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def check_estimates(node, fees_seen):
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"""Call estimatesmartfee and verify that the estimates meet certain invariants."""
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delta = 1.0e-6 # account for rounding error
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last_feerate = float(max(fees_seen))
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all_smart_estimates = [node.estimatesmartfee(i) for i in range(1, 26)]
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for i, e in enumerate(all_smart_estimates): # estimate is for i+1
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feerate = float(e["feerate"])
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assert_greater_than(feerate, 0)
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if feerate + delta < min(fees_seen) or feerate - delta > max(fees_seen):
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raise AssertionError("Estimated fee (%f) out of range (%f,%f)"
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% (feerate, min(fees_seen), max(fees_seen)))
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if feerate - delta > last_feerate:
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raise AssertionError("Estimated fee (%f) larger than last fee (%f) for lower number of confirms"
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% (feerate, last_feerate))
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last_feerate = feerate
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if i == 0:
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assert_equal(e["blocks"], 2)
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else:
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assert_greater_than_or_equal(i + 1, e["blocks"])
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class EstimateFeeTest(BitcoinTestFramework):
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def set_test_params(self):
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self.num_nodes = 3
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# mine non-standard txs (e.g. txs with "dust" outputs)
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self.extra_args = [
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["-acceptnonstdtxn=1", "-maxorphantxsize=1000", "-whitelist=127.0.0.1"],
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["-acceptnonstdtxn=1", "-blockmaxsize=17000", "-maxorphantxsize=1000", "-whitelist=127.0.0.1"],
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["-acceptnonstdtxn=1", "-blockmaxsize=8000", "-maxorphantxsize=1000", "-whitelist=127.0.0.1"]
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]
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def skip_test_if_missing_module(self):
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self.skip_if_no_wallet()
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def setup_network(self):
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"""
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We'll setup the network to have 3 nodes that all mine with different parameters.
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But first we need to use one node to create a lot of outputs
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which we will use to generate our transactions.
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"""
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self.add_nodes(3, extra_args=self.extra_args)
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# Use node0 to mine blocks for input splitting
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# Node1 mines small blocks but that are bigger than the expected transaction rate.
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# NOTE: the CreateNewBlock code starts counting block size at 1,000 bytes,
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# (17k is room enough for 110 or so transactions)
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# Node2 is a stingy miner, that
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# produces too small blocks (room for only 55 or so transactions)
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self.start_nodes()
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self.import_deterministic_coinbase_privkeys()
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self.stop_nodes()
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def transact_and_mine(self, numblocks, mining_node):
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min_fee = Decimal("0.0001")
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# We will now mine numblocks blocks generating on average 100 transactions between each block
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# We shuffle our confirmed txout set before each set of transactions
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# small_txpuzzle_randfee will use the transactions that have inputs already in the chain when possible
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# resorting to tx's that depend on the mempool when those run out
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for i in range(numblocks):
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random.shuffle(self.confutxo)
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for j in range(random.randrange(100 - 50, 100 + 50)):
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from_index = random.randint(1, 2)
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(txhex, fee) = small_txpuzzle_randfee(self.nodes[from_index], self.confutxo,
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self.memutxo, Decimal("0.005"), min_fee, min_fee)
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tx_kbytes = (len(txhex) // 2) / 1000.0
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self.fees_per_kb.append(float(fee) / tx_kbytes)
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self.sync_mempools(self.nodes[0:3], wait=.1)
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mined = mining_node.getblock(mining_node.generate(1)[0], True)["tx"]
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self.sync_blocks(self.nodes[0:3], wait=.1)
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# update which txouts are confirmed
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newmem = []
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for utx in self.memutxo:
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if utx["txid"] in mined:
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self.confutxo.append(utx)
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else:
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newmem.append(utx)
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self.memutxo = newmem
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def run_test(self):
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self.log.info("This test is time consuming, please be patient")
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self.log.info("Splitting inputs so we can generate tx's")
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# Start node0
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self.start_node(0)
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self.txouts = []
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self.txouts2 = []
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# Split a coinbase into two transaction puzzle outputs
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split_inputs(self.nodes[0], self.nodes[0].listunspent(0), self.txouts, True)
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# Mine
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while (len(self.nodes[0].getrawmempool()) > 0):
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self.nodes[0].generate(1)
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# Repeatedly split those 2 outputs, doubling twice for each rep
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# Use txouts to monitor the available utxo, since these won't be tracked in wallet
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reps = 0
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while (reps < 5):
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# Double txouts to txouts2
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while (len(self.txouts) > 0):
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split_inputs(self.nodes[0], self.txouts, self.txouts2)
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while (len(self.nodes[0].getrawmempool()) > 0):
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self.nodes[0].generate(1)
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# Double txouts2 to txouts
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while (len(self.txouts2) > 0):
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split_inputs(self.nodes[0], self.txouts2, self.txouts)
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while (len(self.nodes[0].getrawmempool()) > 0):
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self.nodes[0].generate(1)
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reps += 1
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self.log.info("Finished splitting")
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# Now we can connect the other nodes, didn't want to connect them earlier
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# so the estimates would not be affected by the splitting transactions
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self.start_node(1)
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self.start_node(2)
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connect_nodes(self.nodes[1], 0)
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connect_nodes(self.nodes[0], 2)
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connect_nodes(self.nodes[2], 1)
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self.sync_all()
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self.fees_per_kb = []
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self.memutxo = []
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self.confutxo = self.txouts # Start with the set of confirmed txouts after splitting
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self.log.info("Will output estimates for 1/2/3/6/15/25 blocks")
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for i in range(2):
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self.log.info("Creating transactions and mining them with a block size that can't keep up")
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# Create transactions and mine 10 small blocks with node 2, but create txs faster than we can mine
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self.transact_and_mine(10, self.nodes[2])
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check_estimates(self.nodes[1], self.fees_per_kb)
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self.log.info("Creating transactions and mining them at a block size that is just big enough")
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# Generate transactions while mining 10 more blocks, this time with node1
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# which mines blocks with capacity just above the rate that transactions are being created
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self.transact_and_mine(10, self.nodes[1])
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check_estimates(self.nodes[1], self.fees_per_kb)
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# Finish by mining a normal-sized block:
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while len(self.nodes[1].getrawmempool()) > 0:
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self.nodes[1].generate(1)
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self.sync_blocks(self.nodes[0:3], wait=.1)
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self.log.info("Final estimates after emptying mempools")
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check_estimates(self.nodes[1], self.fees_per_kb)
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if __name__ == '__main__':
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EstimateFeeTest().main()
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